"Even or low came out 3/4 yesterday," Comet says. "I listed every token. Is there a faster way?"
"Add the two probabilities," Wren says. "1/2 plus 1/2 is 1. But that cannot be right."
"Because tokens 2 and 4 got counted twice," Comet says. "They are in both loops."
"So subtract them once," Wren says. "1/2 + 1/2 - 1/4 = 3/4. Same answer as your list."
Nova projects two overlapping loops with the shared part glowing. "Would you like a hint? The glow is the overlap."
"P(A or B) = P(A) + P(B) - P(A and B)," Wren writes. "The addition rule."
"Two ways, one answer," Comet says. "Listing when the set is small, the rule when it is not."
"What do you notice when two events share no outcome?" Wren asks. "Then there is nothing to subtract."
Write every outcome in A, then add the outcomes of B that are not already there. Count, then divide by 8.
Even or high: {2, 4, 6, 8} plus the new high outcome 7 gives {2, 4, 6, 7, 8}. So P = 5/8.
P(A or B) = P(A) + P(B) - P(A and B). Adding P(A) and P(B) counts the overlap twice, so subtract it once.
Even or high: 1/2 + 3/8 - 1/4 = 5/8. The rule agrees with the list.
When A and B share no outcome, P(A and B) = 0 and the rule is just P(A) + P(B). Such events are called disjoint.
| Question | P(A) | P(B) | P(A and B) | P(A or B) |
|---|---|---|---|---|
| even or low | 1/2 | 1/2 | 1/4 | 3/4 |
| even or high | 1/2 | 3/8 | 1/4 | 5/8 |
| odd or even | 1/2 | 1/2 | 0 | 1 |
| low or high | 1/2 | 3/8 | 0 | 7/8 |
"Odd or even" and "low or high" are disjoint pairs: nothing to subtract. Lane 5 is in neither low nor high, so the last row is not 1.
| Statement | True or false? |
|---|---|
| 1/2 + 3/8 - 1/4 = 5/8 | ? |
| P(A or B) can be larger than 1 if A and B are big enough. | ? |
| For disjoint events, P(A or B) = P(A) + P(B). | ? |
| 1/2 + 3/8 = 7/8 | ? |
Two ways that agree. Tomorrow is Data Lab: forty real draws from the bag, tallied two ways at once.