Comet props a clear jug on the bench. Twelve lines are drawn up its side, and a thin tube drains it.
"Twelve lines full. It drops two lines a minute," she says. "What can we make from that?"
"A rule," Wren says. "Lines left: L = 12 - 2t. What do you notice about the sign?"
"Minus two. The level is dropping, so the rate is negative." Comet sketches a line sloping down.
Nova projects the sketch next to yesterday's cart graph. One climbs, one falls.
"Would you like a hint?" she asks. "Where does the falling line reach zero?"
"When the jug is empty," Comet says. "12 - 2t = 0, so t = 6. Six minutes."
Wren labels the axes. "Minutes across, lines up, one square each. Our engineer, your turn to graph."
For the jug, L = 12 - 2t: start at (0, 12). Each minute go right 1 and down 2. The line reaches zero at t = 6.
That point, (6, 0), is the t-intercept. For the jug it means empty after 6 minutes.
From a table: pick two rows, divide the change in output by the change in input.
From a rule: read the number multiplying the input. Both ways agree for a line, so use whichever you have.
Table check for the jug: from t = 1 to t = 4, L goes from 10 to 4. That is a change of -6 over 3 minutes, so -2 a minute.
| Minutes (t) | Lines left (L = 12 - 2t) |
|---|---|
| 0 | 12 |
| 1 | 10 |
| 2 | 8 |
| 3 | 6 |
| 4 | 4 |
| 5 | 2 |
| 6 | 0 |
| Statement | True or false? |
|---|---|
| The graph of L = 12 - 2t is decreasing. | ? |
| The y-intercept of L = 12 - 2t is 6. | ? |
| The point (3, 6) is on the graph of y = 12 - 2t. | ? |
| The point (5, 1) is on the graph of y = 12 - 2t. | ? |
| Two points from a table are enough to find the rate of change of a line. | ? |
| 12 - 2 × 6 = 0 | ? |
Excellent graphing. Tomorrow is Loft Lab: the stopwatch comes out and you time the cart yourself.