"Draw two, count the reds, put them back, shake," Comet says. "Twenty times. Wren keeps the tally."
She draws. Red, blue. "One red." Again. Red, red. "Two." Again. Gold, blue. "Zero."
After twenty rounds Wren reads the tally. "Zero reds 3 times, one red 9 times, two reds 8 times."
"What do you notice?" he asks. "One red is the common case."
Nova projects three bars. "Would you like a hint? Work out what the bag predicts, then compare."
"Two reds is 5/8 × 4/7 = 5/14," Comet says. "Out of twenty, that predicts about 7.1."
"We got 8," Wren says. "Close. Twenty rounds is not forever, and the bag does not owe us anything."
Two draws without replacement make 56 equally likely ordered pairs. Count the pairs for each number of reds.
Zero reds: 3 × 2 = 6 pairs, so P = 3/28. Two reds: 5 × 4 = 20 pairs, so P = 5/14.
One red: red then other, or other then red. 5 × 3 twice is 30 pairs, so P = 15/28.
Check: 3/28 + 15/28 + 5/14 = 1. Every pair is counted once.
Here is the crew's own tally from twenty rounds. Yours will differ, and that is the point of a lab.
| Reds in two draws | Tally (of 20) | Tally as a fraction | Probability from the bag | Predicted count |
|---|---|---|---|---|
| 0 | 3 | 3/20 | 3/28 | 2.1 |
| 1 | 9 | 9/20 | 15/28 | 10.7 |
| 2 | 8 | 2/5 | 5/14 | 7.1 |
The predicted counts are the bag's probabilities times 20. The crew's tally landed close to each, not on it.
Two reds has a second route: C(5, 2) = 10 red pairs out of C(8, 2) = 28 pairs, 5/14. Same answer as the rule.
| What the lab shows | True or false? |
|---|---|
| 3 + 9 + 8 = 20 | ? |
| 3/28 + 15/28 + 5/14 = 1 | ? |
| A tally of twenty rounds must match the bag's probabilities exactly. | ? |
| Two reds can be counted by ordered pairs or by combinations, and both give the same probability. | ? |
Careful lab work. Tomorrow you prove the multiplication rule by counting pairs and use combinations for "at least one".