Wren lays two long rails on the floor, parallel, and a brace across them. "Eight angles, one brace."
Comet sets the protractor at the top crossing. "Angle a is 70. Do I measure the other seven?"
"What do you notice about the bottom crossing?" Wren asks.
"It looks like the top one, slid down the brace." Comet slides her hand along it. "Same slant, because the rails are parallel."
Nova projects the top crossing in gold and slides the copy down to the bottom one. It fits exactly.
"Would you like a hint? A translation along the brace carries one crossing onto the other."
"Then every angle at the bottom matches one at the top," Comet says. "Our designer, prove it and fill in all eight."
Given: two parallel lines cut by a transversal. Prove: angle a is congruent to angle e.
Translate the top crossing along the transversal until it lands on the bottom crossing.
A translation is a rigid motion, so it keeps every angle. It carries the top rail onto the bottom rail because they are parallel.
So it carries angle a exactly onto angle e. Two angles related by a rigid motion are congruent. Done.
Comet measured only angle a: 70°. The rest follow from the two theorems. These are the crew's own numbers.
| Angle | Measure | Reason |
|---|---|---|
| a | 70° | measured |
| b | 110° | straight line with a |
| c | 110° | straight line with a |
| d | 70° | vertical with a |
| e | 70° | corresponding to a |
| f | 110° | corresponding to b |
| g | 110° | corresponding to c |
| h | 70° | corresponding to d |
The bottom edge of a flat runs from A (0, 0) to B (6, 0). Its perpendicular bisector is the line x = 3.
Take P at (3, 4) on that line. PA is 5 and PB is 5. Equal.
Why always? The reflection over the bisector swaps A and B and leaves P alone, so PA and PB are congruent.
The converse holds too: a point equally far from A and B must sit on the bisector. Together: exactly those points.
| Statement | True or false? |
|---|---|
| Corresponding angles on parallel lines are congruent. | ? |
| All eight angles made by a transversal across parallel lines are congruent. | ? |
| 70 + 110 = 180 | ? |
| A point on the perpendicular bisector of AB is equally far from A and B. | ? |
| The proof of corresponding angles used a reflection. | ? |
Eight angles from one reading, designer. Tomorrow is Shop Lab: cardboard braces, torn corners and a midsegment.