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2/6
Week 06 · Two-Step Equations

Tuesday

A group, multiplied
// Undo in reverse order, rewrite to see the puzzle, estimate to check
⏱ about 20 min

Tuesday: A Group, Multiplied

Raven lays out two identical bundles on the workbench. Each bundle is one envelope and 2 beans tied with string.

"Two bundles balance 10 beans," she says. "What do you notice about how to write it?"

"Two of the same group," Rocket says. "2(x + 2) = 10. Everything in the bundle got doubled."

"So you can split the beans two ways," Raven says. "Share the 10 first, or untie the bundles first."

Rocket shares. "10 ÷ 2 = 5. So one bundle is 5. An envelope plus 2 is 5. The envelope is 3."

Nova hovers above the bundles, her light flicking between them. "Now untie them instead," she says. "Same answer, other road."

"2x + 4 = 10," Rocket says, writing. "Subtract 4, divide by 2. Three." Nova hums. "Two roads, one check."

p(x + q) = r: two ways to undo

A level balance: two envelopes and 4 beans on the left, 10 beans on the right.

2(x + 2) = 10 says two equal groups, each an envelope and 2 beans, balance 10 beans.

Road one: divide both sides by 2 first. x + 2 = 5, then subtract 2, so x = 3.

Road two: distribute first. 2(x + 2) = 2x + 4, so 2x + 4 = 10. Subtract 4: 2x = 6. Divide by 2: x = 3.

Both roads reach the same number. Choose the road where the numbers divide evenly.

EquationDivide firstOr distribute firstSolution
2(x + 2) = 10x + 2 = 52x + 4 = 10x = 3
3(x + 2) = 15x + 2 = 53x + 6 = 15x = 3
4(x - 1) = 10x - 1 = 2.54x - 4 = 10x = 3.5
0.5(x + 6) = 7x + 6 = 140.5x + 3 = 7x = 8

Arithmetic road, algebra road

A puzzle can be solved with arithmetic or with algebra, and the operations match up.

The Puzzle Post sign is a rectangle with a perimeter of 54 cm and a length of 6 cm. Arithmetic: 54 ÷ 2 = 27, then 27 - 6 = 21.

Algebra: 2(6 + w) = 54. Divide by 2: 6 + w = 27. Subtract 6: w = 21. The same two operations, in the same order.

TWO ROADS
  • Read the question.
  • Tap your answer.
What is x if 2(x + 2) = 10?
What is x if 3(x + 2) = 15?
What is x if 4(x - 1) = 10?
A rectangle has a perimeter of 54 cm and a length of 6 cm. 2(6 + w) = 54. What is the width w?
THE FIRST UNDO STEP
  • Read the question.
  • Tap your answer.
Undo the first step of 3(x + 2) = 15. What does the equation become?
Undo the first step of 2x + 3 = 11. What does the equation become?
Undo the first step of 5(x - 1) = 20. What does the equation become?
Undo the first step of 4x - 4 = 10. What does the equation become?
SOLVE 3(X + 2) = 15 BY THE DIVIDE-FIRST ROAD
  • ?Write the equation: 3(x + 2) = 15.
  • ?Check: 3 × (3 + 2) = 15.
  • ?Divide both sides by 3: x + 2 = 5.
  • ?Subtract 2 from both sides: x = 3.
WHY THIS EXERCISEDividing first undoes the multiplying of the whole group. Then only one step is left.
Solve 5(x - 1) = 20. What is x?
Solve 0.5(x + 6) = 7. What is x?
Try it
Write 6(x + 1) = 30 on paper. Solve it by dividing first, then again by distributing first.
Circle the road that felt easier and write one sentence saying why.
Draw two bundles, each an envelope and 2 beans tied together, balancing 10 beans. Label it 2(x + 2) = 10.

Two roads, one answer. Tomorrow is Puzzle Lab: two envelopes on the balance and a log of every undo.

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