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Algebra 2 9-12 / Week 06 / Tuesday
2/6
Week 06 · Exponential Functions and Geometric Series

Tuesday

Reading the rate
// Duckweed doubling across the trough
⏱ about 20 min

Tuesday: Reading the Rate

"The shaded end of the trough grows slower," Wren says, pointing at a second column in the log.

"Each day it is 1.1 times the day before. Ten percent more. What do you notice over a week?"

Comet thinks. "Not 70 percent more. The factors multiply. 1.1 to the seventh."

Nova shows the number: about 1.95. "Would you like a hint? A weekly factor of 1.95 means almost doubling each week."

"So the same growth can be read by the day or by the week," Comet says. "Just rewrite the exponent."

"And written as a list, day by day, it is a geometric sequence," Wren says. "Two ways to say one thing."

"Rule or list, factor by day or by week," Comet says. "I like having choices."

Way one: read the daily factor

The shaded patch follows the crew's model P(d) = 4 × 1.1ᵈ. The factor 1.1 means each day has 1.1 times yesterday's count: a 10% rise.

Growth of 10% is a factor of 1 + 0.10 = 1.1. Growth of 25% would be 1.25. A drop of 20% would be 0.8.

Way two: rewrite to read the weekly factor

  1. Start with P(d) = 4 × 1.1ᵈ. A week is 7 days, so write d as 7 × (d/7).
  2. Then 1.1ᵈ = 1.1^(7 × d/7) = (1.1⁷)^(d/7). The exponent rule (aᵐ)ⁿ = aᵐⁿ makes this legal.
  3. Work out 1.1⁷ ≈ 1.95. So P(d) ≈ 4 × 1.95^(d/7).
  4. Read it: every 7 days the count is multiplied by about 1.95. The weekly factor is 1.95, not 1.7.

Same function, two forms. The first shows the daily rate. The second shows the weekly rate. Rewriting an expression reveals what it hides.

For the doubling patch, N(d) = 6 × 2ᵈ = 6 × (2⁷)^(d/7) = 6 × 128^(d/7). The weekly factor is 128.

A geometric sequence, two ways

Written as a list, the doubling counts are 6, 12, 24, 48, 96, ... Each term is the one before times 2: a geometric sequence.

Recursive formula: a₁ = 6 and aₙ = 2 × aₙ₋₁. It says how to get each term from the last one.

Explicit formula: aₙ = 6 × 2ⁿ⁻¹. It gives any term directly. Term 5 is 6 × 2⁴ = 96.

Careful with the count: term 1 is day 0, so term n is day n - 1. That is why the exponent is n - 1.

Compare the forms

FormExampleWhat it showsBest for
daily ruleP(d) = 4 × 1.1ᵈa 1.1 factor each dayone day at a time
weekly ruleP(d) ≈ 4 × 1.95^(d/7)a 1.95 factor each weekplanning a week ahead
recursivea₁ = 6, aₙ = 2 × aₙ₋₁how each term follows the lastfilling in a table
explicitaₙ = 6 × 2ⁿ⁻¹any term directlyjumping to term 20
READ THE RATE
  • Read the question.
  • Tap your answer.
A count grows by a factor of 1.1 each day. By what factor does it grow in 7 days? (Round to 2 places.)
A count grows by a factor of 1.2 each day. By what factor does it grow in 7 days? (Round to 2 places.)
A quantity grows 10% each day. By what factor is it multiplied each day?
A quantity grows 25% each day. By what factor is it multiplied each day?
SEQUENCES TWO WAYS
  • Read the question.
  • Tap your answer.
A geometric sequence starts at 6 and multiplies by 2 each time. What is term 5?
A geometric sequence starts at 5 and multiplies by 3 each time. What is term 4?
Which recursive formula gives the sequence 6, 12, 24, 48?
Which explicit formula gives the sequence 6, 12, 24, 48?
REWRITE P(D) = 4 × 1.1ᵈ BY THE WEEK, IN ORDER
  • ?Work out 1.1⁷ ≈ 1.95
  • ?Write P(d) ≈ 4 × 1.95^(d/7)
  • ?Write the exponent d as 7 × (d/7)
  • ?Use (aᵐ)ⁿ = aᵐⁿ to get (1.1⁷)^(d/7)
  • ?Read the weekly factor: about 1.95
WHY THIS EXERCISERewriting an expression does not change its value. It changes what you can see in it.
StatementTrue or false?
A daily factor of 1.1 gives a weekly factor of 1.7.?
Growth of 10% each day means multiplying by 1.1 each day.?
6 × 2 × 2 × 2 × 2 = 96?
In aₙ = 6 × 2ⁿ⁻¹, term 1 equals 6.?
A recursive formula gives any term without knowing the one before.?
WHY THIS EXERCISEEach form of the rule answers a different question. Knowing which to reach for is the skill.
Try it
Write the sequence 2, 6, 18, 54 on a card. Write its recursive formula on the front and its explicit formula on the back.
Use the explicit formula to find term 7 without writing terms 5 and 6.

Excellent. Tomorrow the beans come out in the Glass House Lab and the doubling gets counted by hand.

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