A grown-up stands by the real winch while the crew builds a small one on the dock bench.
Comet tapes one end of a string to a cardboard tube. "30 centimeters of string on the tube before we start. Now turn."
Wren turns once and measures the string pulled in. "40. Again. 50. Again. 60."
"Ten centimeters every turn," Comet says. "So string on the tube is 10 times turns, plus 30. What do you notice?"
"A straight rule," Wren says. "Which means it runs backwards cleanly."
Nova projects the table beside the tube. "Would you like a hint? Try the backwards question before you turn."
"70 centimeters," Comet calls. Wren writes the inverse, puts in 70, and says "4 turns." Four turns later, the tape agrees.
The crew's numbers are made up for the Boathouse. Yours depend on your tube, and that is the point of a lab.
| Turns (x) | String on the tube (cm) | Backwards |
|---|---|---|
| 0 | 30 | f⁻¹(30) = 0 |
| 1 | 40 | f⁻¹(40) = 1 |
| 2 | 50 | f⁻¹(50) = 2 |
| 3 | 60 | f⁻¹(60) = 3 |
| 4 | 70 | f⁻¹(70) = 4 |
| 5 | 80 | f⁻¹(80) = 5 |
The crew's rule: f(x) = 10x + 30. The inverse: f⁻¹(x) = 0.1x - 3.
Check both ways. f⁻¹(f(4)) = f⁻¹(70) = 4. And f(f⁻¹(70)) = f(4) = 70.
Both compositions give back the number you started with. That is the test for an inverse, and Thursday says why.
| What the lab shows | True or false? |
|---|---|
| The string on the tube grows by the same amount each turn. | ? |
| 10 × 4 + 30 = 70 | ? |
| To run the rule backwards, divide by 10 first and then subtract 30. | ? |
| f(f⁻¹(x)) gives back x for every length in the table. | ? |
| A thicker tube would change the start but not the change per turn. | ? |
Careful lab work. Tomorrow the inverse gets its picture: a mirror across the line y = x.